Escaping in bash. Who knows ?

I have such script for bash:

#!/bin/bash
set -x
a () 

{ 

   echo $1 

}

b () 

{ 

   a "--some-flag='param1 param2,param3'" 

}
b
In the a () function "echo" is called like below:
echo '--some-flag='\''param1' 'param2,param3'\'''

How can I pass parameter to a () function without escaping ?

To make it possible to call echo as follow:
echo --some-flag='param1 param2,param3'

I mean to pass parameters as is?

Installation of Grub2 in Gentoo

I'm bothered to use LILO and want something new.
I've decided to install GRUB2.

1. Unmask package:

echo ">=sys-boot/grub-1.99-r2" >> /etc/portage/package.unmask

2. Build

emerge grub

3. Setup

 grub2-mkconfig -o /boot/grub2/grub.cfg

4. Checking if configuration looks good.

grub2-install --grub-setup=/bin/true /dev/sda

5. Installing

grub2-install /dev/sda

6. Rebooting

reboot.

Apple has lost a visionary genius

Apple has lost a visionary and creative genius, and the world has lost an amazing human being. Those of us who have been fortunate enough to know and work with Steve have lost a dear friend and an inspiring mentor. Steve leaves behind a company that only he could have built, and his spirit will forever be the foundation of Apple.

kernel.org is back

kernel.org is back.
Waiting for results of hacking investigation.

P.S. on lwn.net the link was given to https://www.kernel.org,
secure connection of https://www.kernel.org looks good,
but https://kernel.org says that certificate is only valid for *.kernel sites :-).