Escaping in bash. Who knows ?

I have such script for bash:

#!/bin/bash
set -x
a () 

{ 

   echo $1 

}

b () 

{ 

   a "--some-flag='param1 param2,param3'" 

}
b
In the a () function "echo" is called like below:
echo '--some-flag='\''param1' 'param2,param3'\'''

How can I pass parameter to a () function without escaping ?

To make it possible to call echo as follow:
echo --some-flag='param1 param2,param3'

I mean to pass parameters as is?